8x^2-8x-448=0

Solution for 8x^2-8x-448=0 equation:

8x^2-8x-448=0

a = 8; b = -8; c = -448;
Δ = b2-4ac
Δ = -82-4·8·(-448)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14400}=120$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-120}{2*8}=\frac{-112}{16}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+120}{2*8}=\frac{128}{16}
=8
$